Bit++ Solution

 A. Bit++

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

The classic programming language of Bitland is Bit++. This language is so peculiar and complicated.

The language is that peculiar as it has exactly one variable, called x. Also, there are two operations:

• Operation ++ increases the value of variable x by 1.
• Operation -- decreases the value of variable x by 1.

A statement in language Bit++ is a sequence, consisting of exactly one operation and one variable x. The statement is written without spaces, that is, it can only contain characters "+", "-", "X". Executing a statement means applying the operation it contains.

A programme in Bit++ is a sequence of statements, each of them needs to be executed. Executing a programme means executing all the statements it contains.

You're given a programme in language Bit++. The initial value of x is 0. Execute the programme and find its final value (the value of the variable when this programme is executed).

Input

The first line contains a single integer n (1 ≤ n ≤ 150) — the number of statements in the programme.

Next n lines contain a statement each. Each statement contains exactly one operation (++ or --) and exactly one variable x (denoted as letter «X»). Thus, there are no empty statements. The operation and the variable can be written in any order.

Output

Print a single integer — the final value of x.

Examples

input

1
++X

output

1

input

2
X++
--X

output

0

Solution :

import java.util.Scanner;

public class Bitplusplus {

public static void main(String[] args) {

// TODO Auto-generated method stub

Scanner sc  = new Scanner(System.in);

int no = 0;

int test =  sc.nextInt();

sc.nextLine();

while (test-->0) {

String s = sc.nextLine();

if(s.equals("X++")) 

no++;

if(s.equals("++X")) 

no++;

if(s.equals("X--")) 

no--;

if(s.equals("--X")) 

no--;

}

System.out.println(no);

sc.close();

}

}