Given an array A of N elements. Find the majority element in the array. A majority element in an array A of size N is an element that appears more than N/2 times in the array.
Example 1:
Input:
N = 3
A[] = {1,2,3}
Output:
-1
Explanation:
Since, each element in
{1,2,3} appears only once so there
is no majority element.
Example 2:
Input:
N = 5
A[] = {3,1,3,3,2}
Output:
3
Explanation:
Since, 3 is present more
than N/2 times, so it is
the majority element.
Your Task:
The task is to complete the function majorityElement() which returns the majority element in the array. If no majority exists, return -1.
Expected Time Complexity: O(N).
Expected Auxiliary Space: O(1).
Constraints:
1 <= N <= 107
0 <= Ai <= 106
Solution
class Solution { static int majorityElement(int a[], int size) { // your code here int ans =-1; int[] me = new int[10000000]; for(int i=0;i<size;i++) me[a[i]]++; if(size==1) return a[0]; for(int i=0;i<size+1;i++) if(me[i]>size/2) ans = i; return ans; } }
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