A peak element in an array is the one that is not smaller than its neighbours.
Given an array of size N, find the index of any one of its peak elements.
Example 1:
Input: N = 3 arr[] = {1,2,3} Output: 2 Explanation: index 2 is 3. It is the peak element as it is greater than its neighbour 2.
Example 2:
Input: N = 2 arr[] = {3,4} Output: 1 Explanation: 4 (at index 1) is the peak element as it is greater than its only neighbour element 3.
Your Task:
You don't have to read input or print anything. Complete the function peakElement() which takes the array arr[] and its size N as input parameters and return the index of any one of its peak elements.
Note: The generated output will be 1 if the index that you return is correct. Otherwise output will be 0.
Expected Time Complexity: O(log N)
Expected Auxiliary Space: O(1)
Constraints:
1 <= N <= 105
1 <= A[] <= 106
Solution
class Solution { // Function to find the peak element // arr[]: input array // n: size of array a[] public int peakElement(int[] arr,int n) { if(n==1) return 0; if(arr[0]>arr[1]) return 0; for(int i=1;i<n-1;i++) if(arr[i]>arr[i-1] && arr[i]>arr[i+1]) return i; if(arr[n-1]>arr[n-2]) return n-1; return 0; } }
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